Math, asked by shivyadav5736, 1 year ago

P4+63/4p2-5 by p2-1/4

Answers

Answered by Asahithi
8
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Answered by guptasingh4564
3

The Answer is \frac{4P^{4}+252 }{4P^{4}-9P^{2}+5}

Step-by-step explanation:

Given,

\frac{P^{4}+63 }{4P^{2}-5} by \frac{P^{2}-1}{4}

That means,

\frac{P^{4}+63 }{4P^{2}-5} ÷ \frac{P^{2}-1}{4}

=\frac{P^{4}+63 }{4P^{2}-5}\times \frac{4}{P^{2}-1}

=\frac{4(P^{4}+63)}{(P^{2}-1)(4P^{2}-5)}

=\frac{4P^{4}+252 }{4P^{4}-5P^{2}-4P^{2}+5}

=\frac{4P^{4}+252 }{4P^{4}-9P^{2}+5}

So, The Answer is \frac{4P^{4}+252 }{4P^{4}-9P^{2}+5}

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