Chemistry, asked by paramvir69, 5 months ago

P4+naoh+ h2o = ph3+3 nah2po2 half oxidation and half reduction

Answers

Answered by MohamedFouad

0

Answer:

P4+naoh+ h2o = ph3+3 nah2po2 = P4+Naoh+ h3o = ph4+3 nah6po2

Explanation:

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