p4-(q+r)4 factorise
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Answered by
64
P^4 - (q+R) ^4
= (P^2)^2 - ((q +R) ^2)^2
Apply a^2 - b^2 = (a +b) (a - b)
(P^2 + (Q + R) ^2) (P^2 - (Q + R) ^2)
(P^2 + (Q + R) ^2)(P + Q + R) (P - Q - R)
Thanks
= (P^2)^2 - ((q +R) ^2)^2
Apply a^2 - b^2 = (a +b) (a - b)
(P^2 + (Q + R) ^2) (P^2 - (Q + R) ^2)
(P^2 + (Q + R) ^2)(P + Q + R) (P - Q - R)
Thanks
manisha109:
bt ans is (p-q-r) (p+q+r) (p2+(q+r)2
Answered by
18
Answer:
(p - q - r) (p +q +r) (p^2 + ( q + r) ^2)
Step-by-step explanation:
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