Math, asked by kavinkria1434, 1 year ago

PA AND PB ARE TANGENTS SUCH THAT PA = 9 CM AND ANGLE APB =60. FIND THE LENGTH OF THE CHORD AB

Answers

Answered by anant110
23
The answer is 16 by The formula of Pythagoras theorem
Answered by bhagyashreechowdhury
68

The length of the chord AB is 9 cm.

Step-by-step explanation:

It is given that,

PA and PB are tangents to a circle from external point P touching the circle at A and B .

PA = 9 cm  

∠APB = 60°

We know that if two tangents are drawn to a circle from one external point, then they have equal tangent segments.

PA = PB = 9 cm

∠PBA = ∠PAB ….. [angles opposite to equal sides are equal] ….. (i)

Now consider ΔPAB and applying the angle sum property, we get

∠PBA + ∠PAB + ∠APB = 180°

⇒ ∠PBA + ∠PAB + 60° = 180°

⇒ 2 * ∠PBA = 180° - 60° …… [from eq. (i)]

⇒ 2 * ∠PBA = 120°  

⇒ ∠PBA = 120°/2

∠PBA = 60°

∠PBA = ∠PAB = ∠APB = 60°

Since all the 3 angles of ΔPAB is equal to 60°, therefore, we get that ΔPAB is an equilateral triangle.

We know that all the sides of an equilateral triangle are equal to each other.

PA = PB = AB = 9 cm

Thus, the length of the chord AB of the given circle is 9 cm.

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Also View:

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If AP and AQ are the two tangents a circle with centre O so that ∠POQ = 110°, then ∠PAQ is equal to(a) 60° (b) 70° (c) 80° (d) 90° ?

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