PA and PB are tangents to a circle with Centre O. If angle APB = ( 2 X + 3 )°degree and Angle aob i= ( 3 X + 7 )°degree then find the value of x.
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acc to cyclic quarilateral
angAOB + angAPB =180
3x+7 + 2x+3 =180
5x+10=180
5x = 170
x = 34
This is your answer.
Hope this will help u .
angAOB + angAPB =180
3x+7 + 2x+3 =180
5x+10=180
5x = 170
x = 34
This is your answer.
Hope this will help u .
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