PA And PB are tangents to the circle drawn from the external points P .CD is a third tangent touching the circle at Q .if PB =10 cm and CQ= 2cm then find PC?
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PA = PB = 10 cm (tangents from an external point to a circle are equal)
CQ = CA = 2 cm
PC = PA – AC
= 10 – 2
= 8 cm
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