पांच लगातार सम संख्या A B C D और E का औसत 52 हैं तो B और E का गुणनफल क्या होगा
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Answer:
B×E = 2800
Explanation:
(A+ B+C+D+E)/5 = 52
according to question
B = A+2
C= B+2 = A+4
D = C+2 = 6+A
E = D+2 = A+8
=> (A + (A+2) +(A+4) +(A+6) + (A+8) = 52×5
=> 5A + 20 = 260
=> 5A = 260-20=240
=> A = 240/5
=> A = 48
now
B = A+2
=> B=48+2 = 50
E = A+8
=> E = 48+8 = 56
B×E = (50)×(56)
=> 2800
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