pA =pd andPB=pc show that triangle pab congruent to triangl pdc
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In Triangle PAB and PDC,
Pa = Pd
Now, Divide by Pb on both sides
So,
Pa/pb = Pd/pb
Or,
Pa/pb = Pd/ pc. [ As pb= pc ]
So hence the sides ar din proportion so
Triangle pab is similar to triangle pdc
So Angle p = Angle p
Now we have the angles equals. So by SAS congruence they are congurent
Pa = Pd
Now, Divide by Pb on both sides
So,
Pa/pb = Pd/pb
Or,
Pa/pb = Pd/ pc. [ As pb= pc ]
So hence the sides ar din proportion so
Triangle pab is similar to triangle pdc
So Angle p = Angle p
Now we have the angles equals. So by SAS congruence they are congurent
Answered by
2
Answer:
In Triangle PAB and PDC,
PA = PD
Now, Divide by PB on both sides
So,
PA/PB = PD/PB
Or,
PA/PB = PD/ PC. [ As PB= PC ]
So hence the sides are directly proportion so
Triangle PAB is similar to triangle PDC
So Angle P = Angle P
Now we have the angles equals. So by SAS congruence they are congurent
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