प्र.13 एक त्रिभुज के कोण 2 : 3 : 4 के अनुपात में हैं, तो त्रिभुज के सभी कोण ज्ञात करो।
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Let Triangle ABC be the required triangle.
A:B:C = 2:3:4 - given
Let the common multiple be x.
:. angle BAC = 2x
angle ABC = 3x
angle ACB = 4x
In triangle ABC,
angle ABC + angle BAC + angle ACB = 180° - { sum of measures of all angles in a triangle is 180° }
:. 3x + 2x + 4x = 180°
:. 9x = 180°
:. x = 180°
9
:. x = 20°
Substituting the values,
angle BAC = 2x = 2(20) = 40°
angle ABC = 3x = 3(20) = 60°
angle ACB = 4x = 4(20) = 80°
If you want in Hindi, then I am sorry as I can't translate. You will have to translate on your own !
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