Question

प्र. 36 सिद्ध कीजिए 5-3/7√3 एक अपरिमेय संख्या है।​

Answer 1

Step-by-step explanation:

Given Prove 5-3 / 7√3 is an irrational number.

• Assume 5 – 3 / 7√3 is a rational number.
• Now we need to write this in m/n form where m and n are co- primes.
• So 3/7√3 = 5 – m/n
• Or 5n – m / n = 3/7√3
•     3n / 5n – m = 7√3
•    Or 3n / 7(5n – m) = √3
• Now the left hand side is a rational number and also √3 is an irrational number.
• But a rational number is not equal to an irrational number and so contradicts the assumption .
• Therefore 5 – 3/7√3 is an irrational number

Reference link will be

https://brainly.in/question/8219807