Math, asked by shivamji8435848476, 4 months ago

प्र.8.
यदि (x - 1), बहुपद P(x) = kx2 - 5x + 3 का गुणनखण्ड है, तो K का
मान कीजिए।

Answers

Answered by karan23591

4

Answer:

k = 1

Step-by-step explanation:

x-1

x=1

p(x)=kx2 - 5x + 3

p(1)=k(1)2 - 5(1) + 3

2k - 5 + 3 = 0

2k - 2 = 0

2k = 2

k = 2/2

k = 1

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