Question

प्रूफ दैट एक्स स्क्वायर प्लस 6 एक्स प्लस 5 has no zero​

Answer 1

Answer:

prove that

$x {}^{2} + 6x + 5 \: \\ x {}^{2} + x + 5x + 5 \\ x(x + 1) + 5(x + 1) \\ (x + 5)(x + 1) \\ x = 5 \: and1$

Answer 2

Answer:

prove that

\begin{gathered}x {}^{2} + 6x + 5 \: \\ x {}^{2} + x + 5x + 5 \\ x(x + 1) + 5(x + 1) \\ (x + 5)(x + 1) \\ x = 5 \: and1\end{gathered}

x

2

+6x+5

x

2

+x+5x+5

x(x+1)+5(x+1)

(x+5)(x+1)

x=5and1