प्रूफ दैट प्रूफ दैट द सम ऑफ एनी टू साइड ऑफ़ ट्रायंगल इज ग्रेटर दैन द थर्ड साइड
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∠ABD>∠CDB. Hence we have AD>AB( because the side opposite to a larger angle is longer). AD = AC+BC. Hence the sum of two sides of a triangle is larger than the third side.
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Extend QP to A,
Such that, PA = PR
→ <PAR = < PRA
Since, By the diagram,
=> <ARQ> Z PRA
→ <ARQ > <PAR
→ QA > PQ (Because, the sides opposite to larger angle is larger and the sides opposite to smaller angle is smaller )
→ QP + PA > QR
→QP + PR > QR.
Hence, prove,
Note: similarly we can proved, QP + QR > PR or PR + QR > QP
Thus, The sum of two sides of a triangle is greater than the third side.
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