पैराग्राफ ऑन फोटोस पार्टी
Answers
Answer is in attachment refer to that
Answer:
Answer:
\begin{gathered} \\\tt 6.42 \times 10^8 \times q_1 q_2 \ N \end{gathered}
6.42×10
8
×q
1
q
2
N
Explanation:
Using the coordinates the distance between the particles,
\begin{gathered}\\\tt \sqrt{(2-0)^2 + (-1+0)^2 + (3-0)^2 } \\\\\tt = \sqrt{ 4 +1 +9 } \\\\\tt = \sqrt{14} \ units\end{gathered}
(2−0)
2
+(−1+0)
2
+(3−0)
2
=
4+1+9
=
14
units
Fore between them,
\begin{gathered} \\\tt F = \dfrac{1}{4 \pi \epsilon_{\circ} } \dfrac{ q_1 q_2} {r^2 } \\\tt F= 9 \times 10^9 \times \dfrac{ q_1 q_2}{(\sqrt{14})^2 } N \\\tt = [9 \times 10^9 \times \dfrac{ q_1 q_2}{14 }] N \\\\\tt = 6.42 \times 10^8 \times q_1 q_2 N \end{gathered}
F=
4πϵ
∘
1
r
2
q
1
q
2
F=9×10
9
×
(
14
)
2
q
1
q
2
N
=[9×10
9
×
14
q
1
q
2
]N
=6.42×10
8
×q
1
q
2
N