Question

पूर्ण वर्ग विधि से द्विघात समीकरण 2x^2-5x+3=0 को ६ल कीजिए।​

Answer 1

Answer:

sol

2x^2-5x+3=0

=2xsquare-3x-2x+3=0

=2.x.x-3x-2x+3=0

=x(2x-3) -1(2x-3) =0

=(2x-3) (x-1) =0

either or

2x-3 =0 x-1=0

2x=3 x=1

x=3/2

Answer 2

Given :  $2x^2-5x+3=0$

To find : the value of roots = ?

Solution:

We have,

$2x^2-5x+3=0$

Using the Split the middle terms:

$2x^2-2x-3x+3=0\\\\2x(x-1)-3(x-1)=0\\\\(2x-3)(x-1)\\\\2x-3=0\ or\ x-1=0\\\\x=\dfrac{3}{2}\ or\ x=1$

Hence, the value of x is either 1 or $\dfrac{3}{2}$