Question

पार पर
डे शून्याको का
मोगउन
a PCJ = kx²+2x+ 3k
गुणानफ्ट के बराबर हो तो र
का
मानात
हुरी​

Answer 1

Answer:

$Sum \: of \: the \: zeroes \: = - \frac{b}{a} = - \frac{2}{k} \\ </p><p>Product \: of \: zeroes \: = \frac{c}{a} = \frac{3k}{k} = 3 \\ </p><p>According \: to \: statement \\ </p><p>Sum \: of \: zeroes \: = \: Product \: of \: zeroes \\ - \frac{2}{k} = 3 \\ k = - \frac{2}{3}$

Answer 2

Answer:

$k = - \frac{2}{3}$