_ पार्श्वचित्र में 0 वृत्त का केन्द्र है। ZBAC का मान 40° है। तो ZOBC
तथा ZOCB का मान ज्ञात कीजिए।
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Question :--- we have to find angle OCB ?
Given :- angle BAC = 40°
we know that, angle at centre is double of angle at circumference .
so,
angle BOC = 40 × 2 = 80°
now,
∆BOC is isosceles ∆ as BO=OC = radius of circle ...
so,
angle OBC = angle OCB = (180-80)/2 = 50° (Ans)
(Hope its help you )
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