Question

पार्टिकल ऑफ मास 1.1 केजी 1 टू 1.2 मीटर लोंग स्ट्रिंग इन फील्ड टू परफॉर्म वर्टिकल सर्कुलर मोशन अंडर ग्रेविटी मिनिमम स्पीड ऑफ अ पार्टिकल इज 5 मीटर पर सेकंड कंसीडर द फॉलोइंग स्टेटमेंट फॉर स्पीड मोस्ट P55 5 मीटर पर सेकंड डिफरेंस बिटवीन मैक्सिमम एंड मिनिमम स्टेशन फॉलोइंग इज न्यूटन सिलेक्ट ऑप्शन ​

Answer 1

Answer:

The minimum or critical speed is given by vcritical=√rg . This is the point where the normal (or tension, frictional, etc.) force is 0 and the only thing keeping the object in (circular) motion is the force of gravity.  Neglecting friction and air resistance, a roller coaster car will experience two forces: the force of gravity (Fgrav) and the normal force (Fnorm). The normal force is directed in a direction perpendicular to the track and the gravitational force is always directed downwards.

Unlike horizontal circular motion, in vertical circular motion the speed, as well as the direction of the object, is constantly changing. Gravity is constantly either speeding up the object as it falls, or slowing the object down as it rises.It follows that the tension in the string must therefore be the same at all points, and so the tension (you can find from mass 2, which is m2*g) is equal to the centripetal force causing mass 1 to spin around.