Math, asked by mitthuyadav700, 4 months ago

प्रश्न 16. यूक्लिड विभाजन एल्गोरिद्म की मदद से 960 और 432 का
महत्तम समापवर्तक निकालें।
[2018A/
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Answers

Answered by shrikantpandey15675
1

Answer:

We know that a = bq + r

960 = 432 × 2 + 96

432 = 96 × 4 + 48

96 = 48 × 2 + 0

Since the remainder is 0 so the last divisor will HCF of 960and 432 .

HCF ( 960 × 432 ) = 48

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