प्रश्न : 3 द्विघात बहुपद x 2 - 53x + 6 का शून्यक क्या होगा?
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Step-by-step explanation:
The given equation
x²-53x+6
where a=1 , b= (-53) and c = 6.
By using the Shridhacharya rule,
To check that α and β are correct,
we use the formula (α+β) = -(b/a) and (αβ) = c/a to verify it.
So, ( α+β) = -(b/a)
(52.88655 + 0.11345) = -{(-53)/1}
53 = 53
And (αβ) = c/a
(52.88655× 0.11345 ) = 6/1
5.9999791 = 6
6 = 6 [ approx same, ]
Therefore, 52.88655 and 0.11345 is the zero of the given quadratic equation.
THANKS.
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