Question

प्रश्न.5 बहुपद x2 - 49 के
49 के शुन्यक होगे।
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Answer 1

Step-by-step explanation:

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Answer 2

The zeroes of x in the polynomial $x^2 - 49$ will be +7 , -7 .

Step 1: Find the zeroes of the ppolynomial.

Given -  $x^2 - 49$

Zeroes of the polynomial are : -

$x^2 - 49 = 0$

$(x)^2-(7)^2 =0$

Using the formula, $(a^2-b^2) = (a+b)(a-b)$

$(x+7)(x-7)=0$

So,

$x+7=0$

$x=-7$

or

$x-7=0\\x=7$

Hence, zeroes of polynomial $x^2-49$ is 7, -7 .