प्रश्न 5 समीकरण हल कीजिए- (आलेख विधि से नही)
4x-5y + 16 = 0
2x + y-6 = 0
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4x-5y+16=0 1st equation
2x+y-6=0 2nd equation
2nd multiple by 2,then we get
4x+2y-12=0
Subtract equation 1st and 3rd
4x-5y+16=0
-4x-2y+12=0
_________
0 - 7y+28=0
__________
-7y=-28
Y=-28/-7
Y=4
Put value of y in equation 3rd
4x+2y-12
4x+2(4)-12
4x+8-12=0
4x=4
X=4/4
X=1
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