प्रथम कोटि अभिक्रिया के लिए यदि वेग नियतांक k हो तो अभिक्रिया के 99% को पूरा करने के लिए आवश्यक समय (t) इसके द्वारा दिया जायेगा :
(1) t = 0.693/k
(2) t = 6.909/k
(3) t = 4.606/k
(4) t = 2.303/k
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2) t=0.693/k is the correct answer...
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Answer:
The time required to complete 99% of the reaction will be
t=4.606/k
Explanation:
according to 1st order reaction
t=(2.303/k)log{a/(a-x)}
t=(2.303/k)log{100/(100-99)}
t=4.606/k
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