Math, asked by mayurdahule002, 18 days ago

पितळ या संमिश्रामध्ये तांबे व जस्त यांचे प्रमाण 13:7 असते तर 700 ग्रॅम वजनच्या पितळेच्या भांड्यात जस्त किती असेल ?

Answers

Answered by parigpt1910
1

Step-by-step explanation:

2 kg of Metal (M₁)

1/3rd zinc 2/3rd Coppes.

こ 1/3 x 2 kg

2/3 x2 kg

= 2/3 kg

4/3 kg

Total Zinc in mi Total Copper in mi

Mixture mit M₂.

3kg of Metal (M₂)

1/4th zinc 3/4t Copper

=!1/14X3 kg

= 3/4x3kg

二 314 kg 9/4 kg

Total Zinc Total Coppes in M₂ in m₂

Total zinc in mi + m₂ = 2/3 + 3/4 kg

Total Copper in m,+ m₂ = 4/3+9/4 kg

Ratio - Total zn (mitm₂) Total cal (mit M₂)

2/3,1 3/4

4/3 + 914

Ratio (en/Cu) in the mixture. = 17 43

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