Question

PA² + PB² = A B²
4,0)(ou) play)
1-4 4 4 4 x 4 4 -u) = (4) + (4) ►
716-81 +9² + x + y + 16-89 = 16+16
a729 -81-840
xty-ux-Hy o
- SA: If a=xtiy, ayer and the imaginary por
I is 1 then Lows of a is
xriy-1 Xti (y+1)​

Answer 1

Answer:

p(X)=p(-3)

p(X)=p(-3)therefore X=-3

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)let put the Value of X=-3

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)let put the Value of X=-3X²+kx-2 = -3×-3+k×-3-2

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)let put the Value of X=-3X²+kx-2 = -3×-3+k×-3-29-3k-2

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)let put the Value of X=-3X²+kx-2 = -3×-3+k×-3-29-3k-27-3k

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)let put the Value of X=-3X²+kx-2 = -3×-3+k×-3-29-3k-27-3k-7=-3k

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)let put the Value of X=-3X²+kx-2 = -3×-3+k×-3-29-3k-27-3k-7=-3k7=3k

p(X)=p(-3)therefore X=-3x+3=0 ( you told me)let put the Value of X=-3X²+kx-2 = -3×-3+k×-3-29-3k-27-3k-7=-3k7=3kk=7/3