Pactor of x^3 +7 Kx 2 - 4kx
+123 (2+3) the be values
BIS 15
710
[25
Answers
Answered by
1
Answer:
Since x+3=x-(-3) is a factor of
f(x) =x
3
+7kx
2
−4kx+12
∴ f(-3)=0
or (-3)
3
+7k(-3)
2
-4kx+12
or -27+63k+12k+12=0
or 75k-15=0
or k=
5
1
Step-by-step explanation:
visa answer short and simple
Answered by
0
x³ + 7kx² - 4kx + 12
If (x + 3) is a factor
then substituting (x = -3) into the equation will return us zero.
Solve k:
(-3)³ + 7k(-3)² - 4k(-3) + 12 = 0
-27 + 63k + 12k + 12 = 0
75k - 15 = 0
75k = 15
k = 1/5
Answer: k = 1/5
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