Math, asked by sahilkumar97676, 9 months ago

Pactor of x^3 +7 Kx 2 - 4kx
+123 (2+3) the be values
BIS 15
710
[25​

Answers

Answered by devrami782
1

Answer:

Since x+3=x-(-3) is a factor of

f(x) =x

3

+7kx

2

−4kx+12

∴ f(-3)=0

or (-3)

3

+7k(-3)

2

-4kx+12

or -27+63k+12k+12=0

or 75k-15=0

or k=

5

1

Step-by-step explanation:

visa answer short and simple

Answered by raiarvindkumar7711
0

x³ + 7kx² - 4kx + 12

If (x + 3) is a factor

then substituting (x = -3) into the equation will return us zero.

Solve k:

(-3)³ + 7k(-3)² - 4k(-3) + 12 = 0

-27 + 63k + 12k + 12 = 0

75k - 15 = 0

75k = 15

k = 1/5

Answer: k = 1/5

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