Question

Paga M6.
Date:
4. Find the roots of following
8x² + 2x - 3=0​

Answer 1

Answer:

$\boxed{\bf roots \ are \ \frac{1}{2} \ and \ \frac{-3}{4}}$

Step-by-step explanation:

$Given \ quadratic \ equation,\\8x^2+2x-3=0 \\\\ 8x^2-4x+6x-3=0\\\\4x(2x-1)+3(2x-1)=0 \\\\(2x-1)(4x+3)=0 \\\\ =>2x-1=0 \\ 2x=1\\x=\frac{1}{2} \\\\ =>4x+3=0\\4x=-3\\x=\frac{-3}{4} \\\\ the \ roots \ of \ the \ equation \ are \ \frac{1}{2} \ and \ \frac{-3}{4}$