Page : 1.5
Answer Question No. 7
Attachments:
Answers
Answered by
11
hey dear
here is your answer
here
√2 = 1.41142
√3 = 1.7321
as we take
√2 = a
√ 3 = b
√2 and √3 is
√(√2) * √(√3)
√(√6)
= (6) ^1/4
so first irrational no is
√2 < 6^1/4 < √ 3
in next step
√2 and 6^1/4
√(√2) * 6^1/4. ( solving root)
= 2^1/4 * 6^1/8
so the two irrational number between are
√2( < 2^1/4 * 6^1/8 < 6^1/4 >) √3
so the correct option is d
8√6 and 8√3
hope this helps Sir
thank you
here is your answer
here
√2 = 1.41142
√3 = 1.7321
as we take
√2 = a
√ 3 = b
√2 and √3 is
√(√2) * √(√3)
√(√6)
= (6) ^1/4
so first irrational no is
√2 < 6^1/4 < √ 3
in next step
√2 and 6^1/4
√(√2) * 6^1/4. ( solving root)
= 2^1/4 * 6^1/8
so the two irrational number between are
√2( < 2^1/4 * 6^1/8 < 6^1/4 >) √3
so the correct option is d
8√6 and 8√3
hope this helps Sir
thank you
Anonymous:
is it correct
Option a is correct
OK Sir
If you don't mind, call me bro.
OK
I think a is not correct, bcoz 6^1/8 = 0.75 which is less than 2^1/2
So, C is correct
But, only first part is correct that is, 6^1/4
ok
thank you sir
Answered by
0
Answer:
Correct answer is Option D...
- hope it helps you...
- please mark it as a brainlist answer...
- also please rate thanks and follow me...
- stay home STAY SAFE...
Similar questions