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An artificial satellite takes 30 minutes to complete one revolution. Find the angular speed of the satellite.
Answers
Answered by
5
HEYA BROTHER!!!
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HERE IS YOUR ANSWER :-
>> GIVEN :-
Time taken by the satellite to complete one revolution = 30 mins
>> SOLUTION :-
Time period of satellite (T) = 30 mins
Time in seconds = 30 * 60 (T) = 1800 secs
>> NOW SINCE,
Angular speed (w) = 2(pi) / T
=> (w) = (2 * 3.14) / 1800
=> (w) = 6.28 / 1800
=> (w) = 0.003488 rad/sec
>> THEREFORE,
The angular speed of the satellite is 0.003488 rad/sec (ans).
-------------------------------------------------------------------------------------
HOPE IT HELPS YOU BROTHER,
THANK YOU. ^_^
------------------------------
HERE IS YOUR ANSWER :-
>> GIVEN :-
Time taken by the satellite to complete one revolution = 30 mins
>> SOLUTION :-
Time period of satellite (T) = 30 mins
Time in seconds = 30 * 60 (T) = 1800 secs
>> NOW SINCE,
Angular speed (w) = 2(pi) / T
=> (w) = (2 * 3.14) / 1800
=> (w) = 6.28 / 1800
=> (w) = 0.003488 rad/sec
>> THEREFORE,
The angular speed of the satellite is 0.003488 rad/sec (ans).
-------------------------------------------------------------------------------------
HOPE IT HELPS YOU BROTHER,
THANK YOU. ^_^
Answered by
1
Answer:
The angular speed of satellite is 0.00116 rad/s. The angular speed is the change of the angular displacement with the time. Hence, The angular speed of satellite is 0.00116 rad/s.
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