Question

Page
A Person moves 14 m/s
after 2 second apply
a break. find the distance.
​

Answer 1

Answer:

Distance(s)=14m/s x 2s

=the second or both s is cancelled

Ans=14m x 2

=28m

Step-by-step explanation:

Answer 2

$\Large{\underline{\underline{\bf{\red{Given}}}}}$

• Initial velocity (u) = 14m/s
• Final velocity (v) = 0 {brake applied}
• Time taken (t) = 2sec

$\Large{\underline{\underline{\bf{\red{Find\:out}}}}}$

• Find the distance travelled by a person

$\Large{\underline{\underline{\bf{\red{Solution}}}}}$

According to the first equation of motion

➞ v = u + at

➞ 0 = 14 + a*2

➞ - 14 = 2a

➞ a = -14/2

➞ a = -7m/s²

Now, according to third equation of motion

➞ v² = u² + 2as

➞ (0)² = (14)² + 2*(-7)*s

➞ 0 = 196 - 14s

➞ 14s = 196

➞ s = 196/14 = 14m

Hence, distance travelled by a person i.e 14 m

$\Large{\underline{\underline{\bf{\red{NOTE}}}}}$

• Minus(-) shows retardation of body

• s = ut + ½ at² {2nd equation of motion}