Question

PAGE
DATE
4 find the smallest number which when
Pelivided by 20,30, 40 leaves remainder
Hin each case.

Answer 1

Answer:

ANSWER:

   Required number = 125

GIVEN:

   1st number = 20

   2nd number = 30

   3rd number = 40

TO FIND:

   A number which when divided by 20, 30 and 40 leaves a remainder 5 in each case.

SOLUTION:

Firstly , we have to find the LCM of 20; 30 and 40.

Therefore, LCM:

20,30 and 40 divide 120 completely

so we have to add 5 to have 5 remainder in each case.

Required number = 120+5

= 125

NOTE:

   For this type of question we have to first find the LCM of the given number.

   Then we have to add the remainder which we want to bring.

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Answer 2

Answer:

Answer. 120 is the least common multiple of 20, 30, and 40. So 125 leaves a multiple of 5 when divided by 20, 30, and 40.