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factorise
1-2a-2b-3 (arb)
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Solution :
Detailed explanation of the above factorization :
In step 1, We have written - 2a - 2b as - 2(a+b)
In step 2, We wrote - 2(a+b) as = - 3(a+b)+(a+b) based on the fact, - 3 +1 = - 2
In step 3, then 1, a+b are taken as common from the first 2, last 2 terms respectively.
Next we simplified to get [1 - 3 a - 3 b] [1 + a + b]
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