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Find the value of a and b
that P(x)=x4+ax³-7x²-8x+b
is ė divisible
(x+2)
and (x+3).
exactly
by
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x+2=0
x=-2
x+3=0
x=-3
P(-2)=(-2)^4+a(-2)^3-7(-2)^2-8(-2)+b
=16+(-8)a-28-(-16)+b
=(-8a)-28-b _____1
P(-3)=(-3)^4+a(-3)^3-7(-3)^2-8(-3)+b
=81+(-27)a-(-63)-(-24)+b
=81-27a+63+24+b
= 81-27a+87+b
= -27a+7+b______2
1-2
-8 a -28-b
-27a+ 7+b
_________
-19a-21
__________
a=(-19)
b=21
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