Question

PAGE
Ex: 2
A.2kg, toy truck moving at 4m/s is about to
Collide with a lkg toy car moving at lim's
in the opposite direction find their combined
velocity after collision, if they stick to each other
Neglect friction)​

Answer 1

Answer:

. By momentum conservation,

⇒2(4)−4(2)=2(−2)+4(v2)

=v2=1m/s

b. e=velocity of separationvelocity of approach=−1(−2)4−(−2)=36=0.5

c. AT the maximum deformed state, by coservation of momentum, common velocity is v=0.

JD=m2(v−u2)=4[(0−(−2)]=8Ns

d. Potential energy at the maximum deformed state.

U= loss in kinetic energy during deformation

or U=(12m1u21+12m22)−12(m1+m2)v2

=(122(4)2+124(2)2)−12(2+4)(0)2=24J

e. JR=m2(v2−v)=4(1−0)=4Ns

also JR=eJD=0.5×8=4N

Explanation:

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