Question

Page
• find the area of
of isosceles triangle having the base x cm and each of two equal side is y cm​

Answer 1

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$\bf \underline{Question}$

Page

• find the area of

of isosceles triangle having the base x cm and each of two equal side is y cm

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$\bf \underline{To\: Find}$

• find the area of isosceles triangle

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Let us assume triangle ABC be the given isosceles triangle having sides AB = AC and base BC.

The area of a triangle ABC,

say A having given sides AB and AC equals to y cm and given base BC equals to x cm is given by.

$\sf \: a = \frac{1}{2} (base \times height) \: \:$

Where,:-.

$\sf \: Base =Bc=X cm \\ \sf \: height \: = \sqrt{ {y}^{2} - \frac{ {x}^{2} }{4} } \\ \\ \sf \: a = \frac{1}{2} (base \times height) \: \:$

$\sf = \frac{1}{2} \times x( \sqrt{ {y}^{2} - \frac{ {x}^{2} }{4}) }$

$\sf = \frac{x}{2} ( \sqrt{ {y}^{2} - \frac{ {x}^{2} }{4}) }$