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If sin x=3/5, tan y= 1/2 and π/2<x<π<3π/2
find the value of 8tan x -√5 sec y
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Answer:
sin θ=4/5
tan θ= -4/3
(1/sin θ - 3/4)/(1/cos θ +4/3)
=(5/4-3/4)/(4/3-5/3)
= -3/2
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if cos theta = -3/5, π<theta<3π/2 find the value of cosec theta + cot theta/ sec theta - tan theta
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