Page No.
20
Date
7
A convex lens of focal length 6 cm
is held 4cm from a newspaper which
Has print 0.5cm high. By calculation
determine the size and nature of the
image produced
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Answer:
Explanation:
Given
Focal length, f = 6 cm
Object distance, u = - 4 cm
Size of the object, h = 0.5 cm
To Find,
Size of the image
Nature of the image.
Formula to be used,
Lens formula, 1/f = 1/v - 1/u
Magnification formula, m = v/u = h'/h
Solution,
Putting all the values, we get
1/f = 1/v - 1/u
⇒ 1/6 = 1/v - 1/- 4
⇒ 1/v = 1/6 - 1/4
⇒ 1/v = 2 - 3/12
⇒ 1/v = - 1/12
⇒ v = - 12 cm
Hence, the image is formed at a distance of 12 cm.
Now, the magnification,
Magnification, m = v/u = h'/h
v/u = h'/h
⇒ - 12/- 4 = h'/0.5
⇒ 3 = h'/0.5
⇒ h' = 0.5 × 3
⇒ h' = 1.5 cm.
Hence, the size of the image is 1.5 cm.
The nature of the image is virtual and erect.
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