Question

Page No
calculate the molecular mass of MgSO4.7H2O​

Answer 1

Answer:

Mass of the MgSO4 -7H2O is 12.3 grams.

∵ 6.022 × 10²³ molecules of the  MgSO4 -7H2O is present in the 1 mole of it.

∴ 1 mole of the  MgSO4 -7H2O contains 6.022 × 10²³ molecules.

∴ 246 g of the  MgSO4 -7H2O contains  6.022 × 10²³ molecules.

Thus, 12.3 g of the  MgSO4 -7H2O contains 12.3 × 6.022 × 10²³/246 molecules.

= 0.3011 × 10²³ molecules.

From the Question, number of molecules of the Na₂CO₃ is 0.3011 × 10²³ molecules. (same as  MgSO4 -7H2O)

∵ 1 mole of the Na₂CO₃ contains 6.022 × 10²³ molecules.

∴ 106 g of the Na₂CO₃ contains 6.022 × 10²³ molecules.

or 1 molecules of the Na₂CO₃ weighs 106/(6.022 × 10²³)

∴ 0.3011 × 10²³ molec. of the Na₂CO₃ weighs 106/(6.022 × 10²³) × 0.3011 × 10²³         =  (106 × 0.3011)/6.022 = 5.3 grams.

Thus, the mass of the Sodium carbonate is 5.3 grams.

I hope it will helps you.

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