Question

Page No
Cate:
find a cubic polynomial
with the sum, sum of the
product of its zewes taken
I two at a time, and
the product of its zeroes
are 2 et 7 and 14
respectively​

Answer 1

Answer:

p(x) =  K [ $x^{3}$ - 2$x^{2}$ + 7$x$ - 14]

Step-by-step explanation:

Let the three zeroes of the polynomial be α, β, γ

Let the cubic polynomial be p(x).

p(x) = K [ $x^{3}$ - (α + β + γ) $x^{2}$ + (αβ + βγ + αγ) $x$ - (αβγ)]

p(x) = K [$x^{3}$ - (2) $x^{2}$ + (7) $x$ - (14)]

p(x) =  K [ $x^{3}$ - 2$x^{2}$ + 7$x$ - 14]

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