Chemistry, asked by kaurdamanjot549, 2 days ago

PAGE NO.
DATE
1
The resistance of 0.5N solution of
an electrolyte
in a conductivity cell was found to be as or calculate
the equivalent conductivity of the solution if the
electrodes in the cell are l. 6cm apart and have an
area of 3.8 cm??
1.6cm​

Answers

Answered by anjupundir6530
1

Answer:

The specific conductance of a 0.2NKCl solution at 23∘C is 0.018ohm-1cm-1. The resistance of cell containing the solution at the same tempreature was found to be 45ohm. The cell constant will be

a) 100

b)10

c)100

d) none

PAGE NO.

DATE

1

The resistance of 0.5N solution of

an electrolyte

in a conductivity cell was found to be as or calculate

the equivalent conductivity of the solution if the

electrodes in the cell are l. 6cm apart and have an

area of 3.8 cm??

1.6cm

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