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Date
2) The motion of the particle is defined by the relation
a = (0.8+) m/sec2 whese 't is measured in see It
found that at x = 5m, v
5m, v = 12m I see when t=2sec
Find the position
position and velocity
[Gm]
at t=656c
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Answer:
Step-by-step explanation:
x=8+12t−t
3
v=
dt
dx
=12−3t
2
a=
dt
dv
=−6t
putting v=0
3t
2
=12
t=2sec
a=−6×2=−12ms
−2
Retardation =12ms
−2
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