Math, asked by shubhamkangule1404, 4 months ago

Page No.
Date
2) The motion of the particle is defined by the relation
a = (0.8+) m/sec2 whese 't is measured in see It
found that at x = 5m, v
5m, v = 12m I see when t=2sec
Find the position
position and velocity
[Gm]
at t=656c

Answers

Answered by gyaneshwarsingh882
0

Answer:

Step-by-step explanation:

x=8+12t−t  

3

 

v=  

dt

dx

=12−3t  

2

 

a=  

dt

dv

=−6t

putting v=0

3t  

2

=12

t=2sec

a=−6×2=−12ms  

−2

 

Retardation =12ms  

−2

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