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factorize the following
a) (p3 -3p)2 - 7 (p3-3p) + q [p3 -3p) - 79
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Answer:
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Step-by-step explanation:
Let's simplify step-by-step.
(p3−3p)(2)−7(p3−3p)+q(p3−3p)−79
Distribute:
=(p3)(2)+(−3p)(2)+(−7)(p3)+(−7)(−3p)+(q)(p3)+(q)(−3p)+−79
=2p3+−6p+−7p3+21p+p3q+−3pq+−79
Combine Like Terms:
=2p3+−6p+−7p3+21p+p3q+−3pq+−79
=(p3q)+(2p3+−7p3)+(−3pq)+(−6p+21p)+(−79)
=p3q+−5p3+−3pq+15p+−79
Answer:
=p3q−5p3−3pq+15p−79
sakshijain2004:
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