Page No. Date Find the nature of the the roots of the quadratic equation Bx2tilat 613=0.
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Answer:
4x
2
−5x+3=0
Comparing with ax
2
+bx+c=0, we get, a=4,b=−5,c=3.
Therefore,
D=b
2
−4ac=25−4(4)(3)=25−48=−23<0.
Hence, the given equation has no real roots.
Step-by-step explanation:
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