Question

Page No.:
Date:
find the value of X
x^3- 7x= -6

Answer 1

Answer:

{(3)^3}^7 = 3^7x

3^21=3^7x

3^7x=3^21

When bases are equal then powers are also equal

So, 7x = 21

x= 21/7

x= 3

Step-by-step explanation:

I think it's the answer

Answer 2

Question:

$Find \: the \: value \: of \: x$

${x}^{3} - 7x = - 6$

Answer:

$The \: value \: of \: \underline \bold{x \: is \: 1,2,3}$

To find:

To find the value of x.

Step-by-step explanation:

${x}^{3} - 7x = - 6$

It also can be written as,

$\implies{x}^{3} - 7x + 6 = 0$

We know that,

$(a + b + c + d )= 0$

$\therefore f(1) = 0$

So divide x³-7x+6 with (x-1)

$We \: get\implies {x}^{2} + x - 6 = 0$

Now factorisation

${x}^{2} + x - 6 = 0$

$= (x - 2)(x - 3)$

${x}^{3} - 7x + 6 = 0$

$\implies(x - 1)( {x}^{2} + x - 6) = 0$

$\implies(x - 1)(x - 2)(x - 3) = 0$

$\implies \boxed{x = 1,2,3}$