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find the value of x. y z in
the given figure if ABCD is a parallelogram
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Answer:
x=40°, y=40° and z=40°
Step-by-step explanation:
In quad. ABCD
CF ⊥ AD and CE ⊥ AB
∴ in ΔCEB
by angle sum property
∠CEB + ∠ECB + ∠EBC = 180°
50° + 90° + x = 180°
X = 40°
in a parallelogram opposite angles are equal.
∴ ∠CBA = ∠CDA = 40°
Z = 40°
in tri. DFC, by angle sum property
∠FDC + ∠FCD + ∠DFC = 180°
40° + ∠FCD + 90° = 180°
∠FCD = 50°
in a parallelogram adjecent angles are supplementary
∠ACD + ∠DCB = 180°
40° + ∠DCB = 180°
∠DCB = 140°
∠DCB = ∠FCD + ∠FCE + ∠ECB
140 = 50 + y + 50
Y=40°
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