Question

Page No.
Quer find the soots
factoresation
of the quadratic equation by
IZ 6x² - x-2=0​

Answer 1

The corresponding quadratic polynomial can be factorized as below.

6x2-√2x-2 =0

  6x2-3√2x+2√2x-2 = 0

 3x(2x-√2)+√2(2x-√2) = 0

 (3x+√2)(2x-√2) =0

Now, 6x2-√2x-2=0 gives (3x+√2)(2x-√2) =0, i.e., (3x+√2)=0 or (2x-√2)=0

Therefore, the roots of the given quadratic equation are  - √2/3 and √2/2 = 1/√2

Answer 2

Answer:

I

Step-by-step explanation:

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