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On dividing a
number by 6 and 7
we get 4 as remainder always, find
the highest possible three digit such
number
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Answer:
Answer:
\begin{lgathered}6 \frac{2}{9} \times x = 7 \frac{1}{9} \\ \frac{58}{9} \times x = \frac{64}{9} \\ x = \frac{64}{9} \times \frac{9}{58} \\ x = \frac{32}{29}\end{lgathered}
6
9
2
×x=7
9
1
9
58
×x=
9
64
x=
9
64
×
58
9
x=
29
32
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