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SPLASH
2. calculate the mass percentage of C,H,O
in glucose
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hey here is ur answer
Explanation:
Molecular mass of glucose (C6H12O6) = 6 × 12 + 1 × 12 + 6 × 16 = 72 + 12 + 96 = 180 g.
%of carbon(C) in glucose = 72 /180 × 100 = 40.
% of hydrogen (H) in glucose = 12/ 180 × 100 = 6.66.
% of oxygen(O) in glucose = 96/ 180 × 100 = 53.33.
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