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Prove that in two congruent circles Equal chords are
equidistant from the centre.
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Theorem: Equal chords of a circle are equidistant from its center. Proof: Compare ΔOAX Δ O A X with ΔOCY Δ O C Y . By the RHS criterion, ΔOAX≡ΔOCY Δ O A X ≡ Δ O C Y . Thus, OX = OY, which means that AB and CD are equidistant from O.
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