Question

Pago Me
(iv) Find
the greatest number of 4-digits
which is exactly
exactly divisible
by 40, 48 and 6o.​

Answer 1

Answer:

Find the LCM of the numbers 40, 48, and 60. To do this, do a prime factorization of the three numbers

40=2×2×2×540=2×2×2×5

48=2×2×2×2×348=2×2×2×2×3

60=2×2×3×560=2×2×3×5

All three can be factored using 2, 3, and 5. First take 2. Look for the most times the number 2 is multiplied by itself, which is 2×2×2×22×2×2×2

The 3 is used just once and so it the 5, therefore the LCM is 2×2×2×2×3×5=2402×2×2×2×3×5=240.

Divide 240 into 9,999, the largest who four-digit number to find that the result is 41 with a remainder of 160. Therefore the largest four-digit number that can be divided by 40, 48, and 60 evenly is 240×41=9840240×41=9840.

Step-by-step explanation:

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Answer 2

Answer:

9840 hope you got the same answer